Homework 3 emphasizes alternative methods to direct integration (Coulomb’s Law) for solving the electric field problem including the use of Gauss’ Law and reducing the vector problem to a scalar one by using electric potential. In addition, it introduces the concept of the Dirac delta function as a tool for describing distributions of charge. This homework makes use of what you learned in Secs. 1.5, 2.2, and 2.3 (up to about 2.3.2), but what you know from 2.1 (i.e., superposition of ($\mathbf{E}$) will also be important).
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As we discussed in class, you can break up a disutrubiton of charge into chunks - each a point charge - and add up the contirubtions to the electric field of each chunk. This process forms the basis of numerical superposition, which you began to explore in the last homework - problem 3. In this problem, you will extend that work to a line of charge. You will solve this problem using a Jupyter notebook. You can download it here (or view it here).
Using numerical superposition, adding up the contributions to the electric field due to each chunk, you will solve the following problems.
Now that we have, in principle, fully described how to solve any electrostatics problem (i.e., by adding up the contribution of each chunk of charge), we turn to building our theoretical toolbox by learning alternative methods that make the solving of certain kinds of problems more tractable. The first of these alternatives is Gauss’ Law. It is important to know when and how to apply Gauss’ Law - in the problem below, you are asked to compare Gauss’ Law with Coulomb’s Law.
Consider the following questions in finding the electric field everywhere for a conducting sphere, a uniformly charged sphere, and a sphere with charge distribution varying as $r^n$, all with radius $r_0$ and total charge $Q$:
As you might have picked up by now, spherically symmetric charge distributions are very special. We have a number of theoretical tools we can bring to bear on them and the results we produce are often quite simple in a mathematical sense. In this problem, you will explore these distributions a bit more and connect the mathematics (i.e., the integrals you must do) to the geometry of the problem (i.e., where the charge lives) to gain intuition about these spherically symmetric distributions of charge.
For parts 1 and 2, consider a sphere of radius $R$, centered one the origin, with a radially symmetric charge distribution $\rho(r)$.
What happens when you have problems were the symmetries are mixed? How do you tackle a problem with two different geometries? In this problem, you will explore how to deal with situations where they are two “competing” geometries for the problem. Sometimes you will need to bring two (or more!) aspects of your theoretical toolbox to bear on a problem.
Consider a cube (edge length $a$) with a uniform charge distributed throughout its volume ($\rho$). We carve a spherical cavity out of it of radius $d$, such that the cavity is centered at the center of the cube.
The Dirac delta function is an important theoretical tool for describing distributions of a variety of physical quantities (e.g., mass, charge) where a point object (or system of point objects) is the model we intend to use. In addition, it can be used to describe distributions where these quantities exist in highly constrained spaces (e.g., on a plane or spherical shell). In this class, we will use the Dirac delta function to describe how a charges are distributed. In this problem, you will get familiar with the Dirac delta function for a set point charges on a line.
The linear charge density for a series of charges on the $x$-axis is given by:
\[\lambda(x) = \sum_{n=0}^{10} q_0 n^2\delta\left(x-\dfrac{n}{10}\right)\]Gauss’ Law can be useful in situations where you want to determine the electric field in conceptually different physical spaces. In this problem, you will explore this using the example of a uniformly charged rod with a hole drilled through it.
Consider a rod of length $L$ and radius $b$ that has a hole drilled down the center of it (along it’s length-wise axis) with a radius of $a$. The rod is very long compared to it’s radius, so that Gauss’ Law can be used to find the approximate electric field near the middle of the rod (far from the ends). The rod has a uniform charge distribution $\rho$. You will determine the electric field “everywhere” - meaning everywhere near the middle of the rod.