Day 30 - Calculus of Variations#

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Announcements#

  • Midterm 2 is posted

  • Look for feedback from DC on projects


Seminars this Week#

MONDAY, March 31, 2025#

  • Condensed Matter Seminar 4:10 pm,1400 BPS, Justin Wilson, Louisiana State University, Title: Measurement and Feedback Driven Adaptive Dynamics in the Classical and Quantum Kicked Top

TUESDAY, April 1, 2025#

  • Theory Seminar, 11:00am., FRIB 1200, Kazuyuki Ogata, Kyushu University, Title: “Knock It Out of the Nucleus -Structure of Nuclei Revealed by Knockout Reactions”

  • High Energy Physics Seminar, 1:00 pm, 1400 BPS, Manel Errando, Washington University in St. Louis, Title: Extracting Meson Distribution Amplitudes from Nonlocal Euclidean Correlations at Next-to-Next-to-Leading Order


Seminars this Week#

WEDNESDAY, April 2, 2025#

  • Astronomy Seminar, 1:30 pm, 1400 BPS, Andy Tzandikas, Univ. of Washington, Title: Searching for the Rarest Stellar Occultations

  • PER Seminar, 3:00 pm., BPS 1400, Abigail Daane, Professor of Physics, South Seattle College, Title: The obstacles, stumbles, and growth in examining the “decolonization” of physics education

THURSDAY, April 3, 2025#

  • Colloquium, 3:30 pm, 1415 BPS, Alex Sushkov, Boston University, Title: Nuclear magnetic resonance at the quantum sensitivity limit


Clicker Question 30-1#

The generic segment, ds, of a curve in 2D Cartesian coordinates is given by

ds=(dx)2+(dy)2

The integral of ds from s1 to s2 gives the length of the curve, l. What is the correct expression for l?

  1. l=s1s2ds

  2. l=s1s2(dx)2+(dy)2

  3. l=s1s21+(dy/dx)2dx

  4. l=s1s2(dx/dy)2+1dy

  5. More than one of the above


Clicker Question 30-2#

I can explain why:

s1s2f((Y(x),Y(x),x)dx>s1s2f((y(x),y(x),x)dx

where Y(x)=y(x)+αη(x), the true path plus an error term.

  1. Yes, I can explain why

  2. I think I can explain why

  3. I’m having trouble seeing why

  4. I don’t think I can explain why


Clicker Question 30-3#

For the function Y(x)=y(x)+αη(x), where y(x) is the true path, η(x) is a small error term, and α is a small parameter, what is the derivative of Y(x) with respect to α?

dYdα=?
  1. y(x)

  2. η(x)

  3. η(x)

  4. αη(x)

  5. y(x)+αη(x)


Clicker Question 30-4#

For the function Y(x)=y(x)+αη(x), what is the derivative of Y(x) with respect to α?

dYdα=?
  1. y(x)

  2. η(x)

  3. η(x)

  4. αη(x)

  5. y(x)+αη(x)


Clicker Question 30-5#

The “surface term” that we computed for s1s2η(x)dfdydx is:

[η(x)dfdy]x1x2=0

I can explain why this surface term is equal to zero:

  1. Yes, I can explain why

  2. I think I can explain why

  3. I’m having trouble seeing why

  4. I don’t think I can explain why

  5. I don’t know what a surface term is


Clicker Question 30-6#

We completed this derivation with the following mathematical statement:

s1s2η(x)[fyddx(fy)]=0

where η(x) is an arbitrary function. What does this imply about the term in square brackets?

  1. The term in square brackets must be a pure function of x.

  2. The term in square brackets must be a pure function of y.

  3. The term in square brackets must be a pure function of y.

  4. The term in square brackets must be zero.

  5. The term in square brackets must be a non-zero constant.