What flexibility do we have in defining the vector potential given the Coulomb gauge (A=0)? That is, what can A be that gives us the same B?

  1. A=A+C
  2. A=A+C
  3. A=A+C
  4. A=A+C
  5. Something else?
What flexibility do we have in defining the vector potential given the Coulomb gauge (A=0)? That is, what can A be that gives us the same B? A=A+C A=A+C A=A+C A=A+C Something else? Correct answer: C