On Wednesday, you took an assessment of electromagnetism concepts. **How did that assessment feel for you?** 1. I think it went fine; I felt like I knew most of the answers. 2. I was concerned about one or two questions; but most of the questions were familiar. 3. I guessed (or left blank) most of the questions; none of the questions really felt familiar. Note: * Fall 2016: 3 32 65 0 0
## Announcements * Exams!!! * Evening Exams * Oct 3 (BCH 101) and Nov 7 (1415 BPS), 7pm-9pm * Homework Help Session * Wednesday 5:00pm-6:30pm in 1300 BPS * Thursday 4:30pm-6:00pm in A158 PSS
## Mathematical Preliminaries $\nabla\cdot\mathbf{E} = \frac{\rho}{\epsilon_0} \qquad \int \mathbf{E}\cdot d\mathbf{A} = \int \frac{\rho}{\epsilon_0} d\tau$ $\nabla\cdot\mathbf{B} = 0 \qquad \int \mathbf{B} \cdot d\mathbf{A} = 0$ $\nabla\times\mathbf{E} = - \frac{\partial\mathbf{B}}{\partial t} \qquad \int \mathbf{E} \cdot d\mathbf{l} = - \int \frac{\partial\mathbf{B}}{\partial t} \cdot d\mathbf{A}$ $\nabla\times\mathbf{B} = \mu_0\mathbf{J} + \mu_0\epsilon_0\frac{\partial\mathbf{E}}{\partial t} \qquad \int \mathbf{B} \cdot d\mathbf{A} = \mu_0 \int \left(\mathbf{J} + \epsilon_0 \frac{\partial\mathbf{E}}{\partial t}\right) \cdot d\mathbf{A}$ Note: There's a reason that we are starting with vectors and vector operations; it's inherent in the way electromagnetism is described!
<img src ="./images/charges_in_plane.png" align="right" style="width: 350px";/> Two charges +Q and -Q are fixed a distance r apart. The direction of the force on a test charge -q at A is... 1. Up 2. Down 3. Left 4. Right 5. Some other direction, or $F = 0$ Note: * CORRECT ANSWER: A * Use superposition * Fall 2016:  14 3 8 5; Second vote (after discussion):   0 0 0
In a typical Cartesian coordinate system, vector $\mathbf{A}$ lies along the $+\hat{x}$ direction and vector $\mathbf{B}$ lies along the $-\hat{y}$ direction. What is the direction of $\mathbf{A} \times \mathbf{B}$? 1. $-\hat{x}$ 2. $+\hat{y}$ 3. $+\hat{z}$ 4. $-\hat{z}$ 5. Can't tell Note: * Correct Answer: D * Use the right-hand rule * Fall 2016: 0 0 23 
In a typical Cartesian coordinate system, vector $\mathbf{A}$ lies along the $+\hat{x}$ direction and vector $\mathbf{B}$ lies along the $-\hat{y}$ direction. What is the direction of $\mathbf{B} \times \mathbf{A}$? 1. $-\hat{x}$ 2. $+\hat{y}$ 3. $+\hat{z}$ 4. $-\hat{z}$ 5. Can't tell Note: * Correct Answer: C * Use right-hand rule; means $\mathbf{A} \times \mathbf{B} = - \mathbf{B} \times \mathbf{A}$ * Fall 2016: 0 0  6 0
<img src ="./images/cq_spherical.png" align="right" style="width: 350px";/> ### You derive it Consider the radial unit vector ($\hat{r}$) in the spherical coordinate system as shown in the figure to the right. Determine the $z$ component of this unit vector in the Cartesian $(x,y,z)$ system as a function of $r,\theta,\phi$. Note: This demonstrates that the r unit vector is a curious thing, in fact in contains all the information that is needed to define where you on the unit sphere. The other vectors can be though of as defined relative to that. Altered for F2017 to be shorter, only work on z component
<img src ="./images/cq_vector_in_cylindrical.png" align="right" style="width: 350px";/> In cylindrical (2D) coordinates, what would be the correct description of the position vector $\mathbf{r}$ of the point P shown at $(x,y) = (1, 1)$? 1. $\mathbf{r} = \sqrt{2} \hat{s}$ 2. $\mathbf{r} = \sqrt{2} \hat{s} + \pi/4 \hat{\phi}$ 3. $\mathbf{r} = \sqrt{2} \hat{s} - \pi/4 \hat{\phi}$ 4. $\mathbf{r} = \pi/4 \hat{\phi}$ 5. Something else entirely Note: * CORRECT ANSWER: A * Fall 2016:  90 3 0 1; Second vote (discussion and hint about units):  35 4 1 4
How is the vector $\mathfrak{R}_{12}$ related to $\mathbf{r}_1$ and $\mathbf{r}_2$? <img src ="./images/cq_r1r2.png" align="right" style="width: 350px";/> 1. $\mathfrak{R}_{12} = \mathbf{r}_1 +\mathbf{r}_2$ 1. $\mathfrak{R}_{12} = \mathbf{r}_1 - \mathbf{r}_2$ 1. $\mathfrak{R}_{12} = \mathbf{r}_2 - \mathbf{r}_1$ 4. None of these Note: * CORRECT ANSWER: C * Fall 2016: 6 1  1 0
Coulomb's Law: $\mathbf{F} = \frac{k q_1 q_2}{\left|\mathfrak{R}\right|^2}\hat{\mathfrak{R}}$ where $\mathfrak{R}$ is the relative position vector. In the figure, $q_1$ and $q_2$ are 2 m apart. Which arrow **can** represent $\hat{\mathfrak{R}}$? <img src ="./images/cq_unit_r.png" align="center" style="width: 550px";/> 1. A 2. B 3. C 4. More than one (or NONE) of the above 5. You can't decide until you know if $q_1$ and $q_2$ are the same or opposite charges Note: * CORRECT ANSWER: D * A unit vector has no units; so it's length is meaningless on a picture with units. * Fall 2016 (hint given while still open): 14 10 9  23; students wanted to discuss E