<img src="./images/parallel_currents.png" align="right" style="width: 250px";/>
I have two very long, parallel wires each carrying a current $I_1$ and $I_2$, respectively. In which direction is the force on the wire with the current $I_2$?
1. Up
2. Down
3. Right
4. Left
5. Into or out of the page
Note:
* CORRECT ANSWER: D
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## Potter Houses
<img src="./images/Houses.png" align="center" style="width: 800px";/>
What is $\oint \mathbf{B}\cdot d\mathbf{l}$ around this purple (dashed) Amperian loop?
<img src="./images/two_loops_ampere.png" align="left" style="width: 400px";/>
1. $\mu_0 (|I_2 | +|I_1 |)$
2. $\mu_0 (|I_2|-|I_1|)$
3. $\mu_0 (| I_2 | + | I_1 | \sin \theta)$
4. $\mu_0 (| I_2 | - | I_1 | \sin \theta)$
5. $\mu_0 (| I_2 | + | I_1 | \cos\theta)$
Note:
* CORRECT ANSWER: A
Stoke's Theorem says that for a surface $S$ bounded by a perimeter $L$, any vector field $\mathbf{B}$ obeys:
<img src="./images/balloon_surface.png" align="right" style="width: 300px";/>
$$\int_S (\nabla \times \mathbf{B}) \cdot dA = \oint_L \mathbf{B} \cdot d\mathbf{l}$$
Does Stoke's Theorem apply for any surface $S$ bounded by a perimeter $L$, even this balloon-shaped surface $S$?
1. Yes
2. No
3. Sometimes
Note:
* CORRECT ANSWER: A
Rank order $\int \mathbf{J} \cdot d\mathbf{A}$ (over blue surfaces) where $\mathbf{J}$ is uniform, going left to right:
<img src="./images/current_surfaces.png" align="center" style="width: 600px";/>
1. iii > iv > ii > i
2. iii > i > ii > iv
3. i > ii > iii > iv
4. Something else!!
5. Not enough info given!!
Note:
* CORRECT ANSWER: D
* They are all the same!
<img src="./images/loop_infinite_wire.jpg" align="right" style="width: 250px";/>
Much like Gauss's Law, Ampere's Law is always true (for magnetostatics), but only useful when there's sufficient symmetry to "pull B out" of the integral.
So we need to build an argument for what $\mathbf{B}$ looks like and what it can depend on.
For the case of an infinitely long wire, can $\mathbf{B}$ point radially (i.e., in the $\hat{s}$ direction)?
1. Yes
2. No
3. ???
Note:
* CORRECT ANSWER: B
* It violates Gauss's Law for B
<img src="./images/loop_infinite_wire.jpg" align="right" style="width: 250px";/>
Continuing to build an argument for what $\mathbf{B}$ looks like and what it can depend on.
For the case of an infinitely long wire, can $\mathbf{B}$ depend on $z$ or $\phi$?
1. Yes
2. No
3. ???
Note:
* CORRECT ANSWER: B
* By symmetry it cannot
<img src="./images/loop_infinite_wire.jpg" align="right" style="width: 250px";/>
Finalizing the argument for what $\mathbf{B}$ looks like and what it can depend on.
For the case of an infinitely long wire, can $\mathbf{B}$ have a $\hat{z}$ component?
1. Yes
2. No
3. ???
Note:
* CORRECT ANSWER: B
* Biot-Savart suggests it cannot
For the infinite wire, we argued that $\mathbf{B}(\mathbf{r}) = B(s)\hat{\phi}$. For the case of an infinitely long **thick** wire of radius $a$, is this functional form still correct? Inside and outside the wire?
1. Yes
2. Only inside the wire ($s<a$)
3. Only outside the wire ($s>a$)
4. No
Note:
* CORRECT ANSWER: A