Consider a single point charge at the origin. It will have ONLY a monopole contribution to the potential at a location r=⟨x,y,z⟩.
As we have seen, if we move the charge to another location (e.g., r′=⟨0,0,d⟩), the distribution now has a dipole contribution to the potential at r!
What the hell is going on here?
- It's just how the math works out. Nothing has changed physically at r.
- There is something different about the field at r and the potential is showing us that.
- I'm not sure how to resolve this problem.
Polarization


A stationary point charge +Q is near a block of polarization material (a linear dielectric). The net electrostatic force on the block due to the point charge is:
- attractive (to the left)
- repulsive (to the right)
- zero

The sphere below (radius a) has uniform polarization P0, which points in the +z direction.
What is the total dipole moment of this sphere?
- zero
- P0a3
- 4πa3P0/3
- P0
- None of these/must be more complicated

The cube below (side a) has uniform polarization P0, which points in the +z direction.
What is the total dipole moment of this cube?
- zero
- a3P0
- P0
- P0/a3
- 2P0a2
In the following case, is the bound surface and volume charge zero or nonzero?

- σb=0,ρb≠0
- σb≠0,ρb≠0
- σb=0,ρb=0
- σb≠0,ρb=0
In the following case, is the bound surface and volume charge zero or nonzero?

- σb=0,ρb≠0
- σb≠0,ρb≠0
- σb=0,ρb=0
- σb≠0,ρb=0
Consider a single point charge at the origin. It will have ONLY a monopole contribution to the potential at a location r=⟨x,y,z⟩.
As we have seen, if we move the charge to another location (e.g., r′=⟨0,0,d⟩), the distribution now has a dipole contribution to the potential at r!
What the hell is going on here?
It's just how the math works out. Nothing has changed physically at r.
There is something different about the field at r and the potential is showing us that.
I'm not sure how to resolve this problem.