Consider a single point charge at the origin. It will have ONLY a monopole contribution to the potential at a location $\mathbf{r} = \langle x,y,z\rangle$.
As we have seen, if we move the charge to another location (e.g., $\mathbf{r}' = \langle 0,0,d \rangle$), the distribution now has a dipole contribution to the potential at $\mathbf{r}$!
What the hell is going on here?
1. It's just how the math works out. Nothing has changed physically at $\mathbf{r}$.
2. There is something different about the field at $\mathbf{r}$ and the potential is showing us that.
3. I'm not sure how to resolve this problem.
## Polarization
<img src="./images/diel.gif" align="center" style="width: 400px";/>
<img src="./images/charge_near_block.png" align="right" style="width: 400px";/>
A stationary point charge $+Q$ is near a block of polarization material (a linear dielectric). The net electrostatic force on the block due to the point charge is:
1. attractive (to the left)
2. repulsive (to the right)
3. zero
Note:
* CORRECT ANSWER: A
<img src="./images/sphere_p0_z.png" align="right" style="width: 300px";/>
The sphere below (radius $a$) has uniform polarization $\mathbf{P}_0$, which points in the $+z$ direction.
What is the total dipole moment of this sphere?
1. zero
2. $\mathbf{P}_0 a^3$
3. $4\pi a^3 \mathbf{P}_0/3$
4. $\mathbf{P}_0$
5. None of these/must be more complicated
Note:
* CORRECT ANSWER: C
<img src="./images/cube_p0_z.png" align="right" style="width: 300px";/>
The cube below (side $a$) has uniform polarization $\mathbf{P}_0$, which points in the $+z$ direction.
What is the total dipole moment of this cube?
1. zero
2. $a^3 \mathbf{P}_0$
3. $\mathbf{P}_0$
4. $\mathbf{P}_0/a^3$
5. $2 \mathbf{P}_0 a^2$
Note:
* CORRECT ANSWER: B
In the following case, is the bound surface and volume charge zero or nonzero?
<img src="./images/mini_dipoles_matter_1.png" align="center" style="width: 400px";/>
1. $\sigma_b = 0, \rho_b \neq 0$
2. $\sigma_b \neq 0, \rho_b \neq 0$
3. $\sigma_b = 0, \rho_b=0$
4. $\sigma_b \neq 0, \rho_b=0$
Note:
* CORRECT ANSWER: D
In the following case, is the bound surface and volume charge zero or nonzero?
<img src="./images/mini_dipoles_matter_2.png" align="center" style="width: 400px";/>
1. $\sigma_b = 0, \rho_b \neq 0$
2. $\sigma_b \neq 0, \rho_b \neq 0$
3. $\sigma_b = 0, \rho_b=0$
4. $\sigma_b \neq 0, \rho_b=0$
Note:
* CORRECT ANSWER: B