The general solution for the electric potential in spherical coordinates with azimuthal symmetry (no ϕ dependence) is:
V(r,θ)=∞∑l=0(Alrl+Blrl+1)Pl(cosθ)
Consider a metal sphere (constant potential in and on the sphere, remember). Which terms in the sum vanish outside the sphere? (Recall: V→0 as r→∞)
All the Al's
All the Al's except A0
All the Bl's
All the Bl's except B0
Something else
Given V0(θ)=∑lClPl(cosθ), we want to get to the integral:
∫+1−1Pl(u)Pm(u)du=22+1(forl=m)
we can do this by multiplying both sides by:
Pm(cosθ)
Pm(sinθ)
Pm(cosθ)sinθ
Pm(sinθ)cosθ
Pm(sinθ)sinθ
V(r,θ)=∞∑l=0(Alrl+Blrl+1)Pl(cosθ)
Suppose V on a spherical shell is:
V(R,θ)=V0(1+cos2θ)
Which terms do you expect to appear when finding V(inside)?
Many Al terms (but no Bl's)
Many Bl terms (but no Al's)
Just A0 and A2
Just B0 and B2
Something else!
V(r,θ)=∞∑l=0(Alrl+Blrl+1)Pl(cosθ)
Suppose V on a spherical shell is:
V(R,θ)=V0(1+cos2θ)
Which terms do you expect to appear when finding V(outside)?
Many Al terms (but no Bl's)
Many Bl terms (but no Al's)
Just A0 and A2
Just B0 and B2
Something else!
How many boundary conditions (on the potential V) do you use to find V inside the spherical plastic shell?
1
2
3
4
It depends on V0(θ)
The general solution for the electric potential in spherical coordinates with azimuthal symmetry (no ϕ dependence) is:
V(r,θ)=∞∑l=0(Alrl+Blrl+1)Pl(cosθ)
Consider a metal sphere (constant potential in and on the sphere, remember). Which terms in the sum vanish outside the sphere? (Recall: V→0 as r→∞)
All the Al's
All the Al's except A0
All the Bl's
All the Bl's except B0
Something else
CORRECT ANSWER: E
Only B0 will survive.