We derived that the electric field due to an infinite sheet with charge density σ was as follows:

E(z)={σ2ε0ˆkif z > 0σ2ε0ˆkif z < 0

What does that tell you about the difference in the field when we cross the sheet, E(+z)E(z)?

  1. it's zero
  2. it's σε0
  3. it's -σε0
  4. it's +σε0ˆk
  5. it's -σε0ˆk
We derived that the electric field due to an infinite sheet with charge density σ was as follows: E(z)={σ2ε0ˆkif z > 0σ2ε0ˆkif z < 0 What does that tell you about the difference in the field when we cross the sheet, E(+z)E(z)? it's zero it's σε0 it's -σε0 it's +σε0ˆk it's -σε0ˆk CORRECT ANSWER: D Makes for a good discussion about cross one direction versus the other